1+x+2x 2+3x 3

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【ベストコレクション】 f(x)=2(1/7)^x 330589-F(x)=2(1/7)^x

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Integral of 1/(x^2+2x+2) (substitution)Solve by completing the square x^2 -2x 【ベストコレクション】 f(x)=2(1/7)^x 330589-f(x)=2(1/7)^x[新しいコレクション] x 3/x-3 x 2/x-2=2 228406-x^3+x-(x-2)(x^2+2x+4).

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